Interaction of molybdate with copper(II)-histidine.
Molybdate and copper(II)-histidine form an insoluble complex of empirical formula Cu2(His)3(MoO4)2(H2O)2ESR-spectroscopy indicated that the complex had tetragonal symmetry. IR-spectroscopy showed the presence of a carboxylate anion and suggested that the molybdate ion formed an ammonium-type salt with the nitrogens of the imidazole. The complex did not form following dissociation of the protonated imidazole (above a pH of approximately 6).
D055598:Chemical Phenomena; D002621:Chemistry; D003300:Copper; D004578:Electron Spin Resonance Spectroscopy; D006639:Histidine; D008982:Molybdenum; D009942:Organometallic Compounds; D013055:Spectrophotometry, Infrared
D009942:Organometallic Compounds; D006639:Histidine; D003300:Copper; D008982:Molybdenum