Assignment of human elongation factor 1alpha genes: EEF1A maps to chromosome 6q14 and EEF1A2 to 20q13.3.
The human elongation factor 1alpha gene family consists of at least 2 actively transcribed genes, EEF1A and EEF1A2, and more than 18 homologous loci. EEF1A2 is expressed in a tissue-specific manner, whereas EEF1A is expressed ubiquitously, and both of them can function in translation. An EEF1A cDNA probe has previously been shown to cross-hybridize with several human chromosomes, but the location of the functional gene has not been established. We have mapped the functional EEF1A gene to 6q14 by combined fluorescence in situ hybridization (FISH) and PCR analysis of a somatic cell hybrid panel and mapped EEF1A2 to 20q13.3 by FISH. In addition, the 11 strongest cross-hybridizing loci (EEF1AL2-EEF1AL13) were mapped by FISH to 12p12, 9q34, 7p15-p21, 19q13, 3q26-q27, 7q33-q35, 1p13-p22, 2q12-q14, 5p12-q11, 1q31-q32, and Xq21.
Lund
A
A
Department of Biostructural Chemistry, Aarhus University, Aarhus, Denmark.
Knudsen
S M
SM
Vissing
H
H
Clark
B
B
Tommerup
N
N
D001483:Base Sequence; D002890:Chromosomes, Human, Pair 20; D002896:Chromosomes, Human, Pair 6; D018076:DNA, Complementary; D006801:Humans; D017404:In Situ Hybridization, Fluorescence; D008969:Molecular Sequence Data; D020648:Peptide Elongation Factor 1; D010445:Peptide Elongation Factors / Q000235:genetics*
D018076:DNA, Complementary; D020648:Peptide Elongation Factor 1; D010445:Peptide Elongation Factors