title: Reduction and oxidation of hydroperoxo rhodium(III) complexes by halides and hypobromous acid.
abstract: Oxygen atom transfer from trans-L(H(2)O)RhOOH(2+) [L = [14]aneN(4) (L(1)), meso-Me(6)[14]aneN(4) (L(2)), and (NH(3))(4)] to iodide takes place according to the rate law -d[L(H(2)O)RhOOH(2+)]/dt = k(I)[L(H(2)O)RhOOH(2+)][I(-)][H(+)]. At 0.10 M ionic strength and 25 degrees C, the rate constant k(I)/M(-)(2) s(-)(1) has values of 8.8 x 10(3) [L = (NH(3))(4)], 536 (L(1)), and 530 (L(2)). The final products are LRh(H(2)O)(2)(3+) and I(2)/I(3)(-). The (NH(3))(4)(H(2)O)RhOOH(2+)/Br(-) reaction also exhibits mixed third-order kinetics with k(Br) approximately 1.8 M(-)(2) s(-)(1) at high concentrations of acid (close to 1 M) and bromide (close to 0.1 M) and an ionic strength of 1.0 M. Under these conditions, Br(2)/Br(3)(-) is produced in stoichiometric amounts. As the concentrations of acid and bromide decrease, the reaction begins to generate O(2) at the expense of Br(2), until the limit at which [H(+)] <or= 0.10 M and [Br(-)] <or= 0.010 M, when Br(2)/Br(3)(-) is no longer observed and O(2) is produced quantitatively. At this limit, the loss of (NH(3))(4)(H(2)O)RhOOH(2+) is about twice as fast as it is at the high [H(+)] and [Br(-)] extreme, and the stoichiometry is 2(NH(3))(4)(H(2)O)RhOOH(2+) --> 2(NH(3))(4)(H(2)O)RhOH(2+) + O(2); i.e., the reaction has turned into the bromide-catalyzed disproportionation of coordinated hydroperoxide. In the proposed mechanism, the hydrolysis of the initially formed Br(2) produces HOBr, the active oxidant for the second equivalent of (NH(3))(4)(H(2)O)RhOOH(2+). The rate constant k(HOBr) for the HOBr/(NH(3))(4)(H(2)O)RhOOH(2+) reaction is 2.9 x 10(8) M(-)(1) s(-)(1).
authors.affiliation: Ames Laboratory, Iowa State University of Science and Technology, Ames, Iowa 50011, USA.
authors.forename: Kelemu
authors.initials: K
authors.lastname: Lemma
authors.forename: Andreja
authors.initials: A
authors.lastname: Bakac